2(c-4)=6c+8

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Solution for 2(c-4)=6c+8 equation: 



2(c-4)=6c+8

We move all terms to the left:

2(c-4)-(6c+8)=0

We multiply parentheses

2c-(6c+8)-8=0

We get rid of parentheses

2c-6c-8-8=0

We add all the numbers together, and all the variables

-4c-16=0

We move all terms containing c to the left, all other terms to the right

-4c=16

c=16/-4

c=-4

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