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6-1/3x=2/5x+4
We move all terms to the left:
6-1/3x-(2/5x+4)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x+4)!=0We get rid of parentheses
x∈R
-1/3x-2/5x-4+6=0
We calculate fractions
(-5x)/15x^2+(-6x)/15x^2-4+6=0
We add all the numbers together, and all the variables
(-5x)/15x^2+(-6x)/15x^2+2=0
We multiply all the terms by the denominator
(-5x)+(-6x)+2*15x^2=0
Wy multiply elements
30x^2+(-5x)+(-6x)=0
We get rid of parentheses
30x^2-5x-6x=0
We add all the numbers together, and all the variables
30x^2-11x=0
a = 30; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·30·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*30}=\frac{0}{60} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*30}=\frac{22}{60} =11/30 $
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