2(c+3)+11(d-4)=

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Solution for 2(c+3)+11(d-4)= equation:


Simplifying
2(c + 3) + 11(d + -4) = 0

Reorder the terms:
2(3 + c) + 11(d + -4) = 0
(3 * 2 + c * 2) + 11(d + -4) = 0
(6 + 2c) + 11(d + -4) = 0

Reorder the terms:
6 + 2c + 11(-4 + d) = 0
6 + 2c + (-4 * 11 + d * 11) = 0
6 + 2c + (-44 + 11d) = 0

Reorder the terms:
6 + -44 + 2c + 11d = 0

Combine like terms: 6 + -44 = -38
-38 + 2c + 11d = 0

Solving
-38 + 2c + 11d = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '38' to each side of the equation.
-38 + 2c + 38 + 11d = 0 + 38

Reorder the terms:
-38 + 38 + 2c + 11d = 0 + 38

Combine like terms: -38 + 38 = 0
0 + 2c + 11d = 0 + 38
2c + 11d = 0 + 38

Combine like terms: 0 + 38 = 38
2c + 11d = 38

Add '-11d' to each side of the equation.
2c + 11d + -11d = 38 + -11d

Combine like terms: 11d + -11d = 0
2c + 0 = 38 + -11d
2c = 38 + -11d

Divide each side by '2'.
c = 19 + -5.5d

Simplifying
c = 19 + -5.5d

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