5/(2b-3)=1/(3b+1)

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Solution for 5/(2b-3)=1/(3b+1) equation:


D( b )

3*b+1 = 0

2*b-3 = 0

3*b+1 = 0

3*b+1 = 0

3*b+1 = 0 // - 1

3*b = -1 // : 3

b = -1/3

2*b-3 = 0

2*b-3 = 0

2*b-3 = 0 // + 3

2*b = 3 // : 2

b = 3/2

b in (-oo:-1/3) U (-1/3:3/2) U (3/2:+oo)

5/(2*b-3) = 1/(3*b+1) // - 1/(3*b+1)

5/(2*b-3)-(1/(3*b+1)) = 0

5/(2*b-3)-(3*b+1)^-1 = 0

5/(2*b-3)-1/(3*b+1) = 0

(5*(3*b+1))/((2*b-3)*(3*b+1))+(-1*(2*b-3))/((2*b-3)*(3*b+1)) = 0

5*(3*b+1)-1*(2*b-3) = 0

13*b+8 = 0

(13*b+8)/((2*b-3)*(3*b+1)) = 0

(13*b+8)/((2*b-3)*(3*b+1)) = 0 // * (2*b-3)*(3*b+1)

13*b+8 = 0

13*b+8 = 0 // - 8

13*b = -8 // : 13

b = -8/13

b = -8/13

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