2(b-6)-4=12

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Solution for 2(b-6)-4=12 equation: 



2(b-6)-4=12

We move all terms to the left:

2(b-6)-4-(12)=0

We add all the numbers together, and all the variables

2(b-6)-16=0

We multiply parentheses

2b-12-16=0

We add all the numbers together, and all the variables

2b-28=0

We move all terms containing b to the left, all other terms to the right

2b=28

b=28/2

b=14

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