(-21/2)h=-20

Solution for (-21/2)h=-20 equation:

(-21/2)h=-20

We move all terms to the left:

(-21/2)h-(-20)=0


Domain of the equation: 2)h!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

(-21/2)h+20=0

We multiply parentheses

-21h^2+20=0

a = -21; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·(-21)·20
Δ = 1680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1680}=\sqrt{16*105}=\sqrt{16}*\sqrt{105}=4\sqrt{105}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{105}}{2*-21}=\frac{0-4\sqrt{105}}{-42}
=-\frac{4\sqrt{105}}{-42}
=-\frac{2\sqrt{105}}{-21}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{105}}{2*-21}=\frac{0+4\sqrt{105}}{-42}
=\frac{4\sqrt{105}}{-42}
=\frac{2\sqrt{105}}{-21}
$