2(b-3)-4=3(b-7)

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Solution for 2(b-3)-4=3(b-7) equation:


Simplifying
2(b + -3) + -4 = 3(b + -7)

Reorder the terms:
2(-3 + b) + -4 = 3(b + -7)
(-3 * 2 + b * 2) + -4 = 3(b + -7)
(-6 + 2b) + -4 = 3(b + -7)

Reorder the terms:
-6 + -4 + 2b = 3(b + -7)

Combine like terms: -6 + -4 = -10
-10 + 2b = 3(b + -7)

Reorder the terms:
-10 + 2b = 3(-7 + b)
-10 + 2b = (-7 * 3 + b * 3)
-10 + 2b = (-21 + 3b)

Solving
-10 + 2b = -21 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-10 + 2b + -3b = -21 + 3b + -3b

Combine like terms: 2b + -3b = -1b
-10 + -1b = -21 + 3b + -3b

Combine like terms: 3b + -3b = 0
-10 + -1b = -21 + 0
-10 + -1b = -21

Add '10' to each side of the equation.
-10 + 10 + -1b = -21 + 10

Combine like terms: -10 + 10 = 0
0 + -1b = -21 + 10
-1b = -21 + 10

Combine like terms: -21 + 10 = -11
-1b = -11

Divide each side by '-1'.
b = 11

Simplifying
b = 11

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