(2/3x-12/11)(7/4x-1/12)=0

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Solution for (2/3x-12/11)(7/4x-1/12)=0 equation: 


x in (-oo:+oo)

((2/3)*x-(12/11))*((7/4)*x-(1/12)) = 0

((2/3)*x-12/11)*((7/4)*x-1/12) = 0

(2/3*x-12/11)*(7/4*x-1/12) = 0

( 2/3*x-12/11 )

2/3*x-12/11 = 0 // + 12/11

2/3*x = 12/11 // : 2/3

x = 12/11/2/3

x = 18/11

( 7/4*x-1/12 )

7/4*x-1/12 = 0 // + 1/12

7/4*x = 1/12 // : 7/4

x = 1/12/7/4

x = 1/21

x in { 18/11, 1/21 }

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