2(b+5)=3(4+b)

Solution for 2(b+5)=3(4+b) equation:

2(b+5)=3(4+b)

We move all terms to the left:

2(b+5)-(3(4+b))=0

We add all the numbers together, and all the variables

2(b+5)-(3(b+4))=0

We multiply parentheses

2b-(3(b+4))+10=0


We calculate terms in parentheses: -(3(b+4)), so:

3(b+4)

We multiply parentheses

3b+12

Back to the equation:

-(3b+12)


We get rid of parentheses

2b-3b-12+10=0

We add all the numbers together, and all the variables

-1b-2=0

We move all terms containing b to the left, all other terms to the right

-b=2

b=2/-1

b=-2