-k+10=6-4(5+k)

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Solution for -k+10=6-4(5+k) equation: 



-k+10=6-4(5+k)

We move all terms to the left:

-k+10-(6-4(5+k))=0

We add all the numbers together, and all the variables

-k-(6-4(k+5))+10=0

We add all the numbers together, and all the variables

-1k-(6-4(k+5))+10=0



We calculate terms in parentheses: -(6-4(k+5)), so:

6-4(k+5)

determiningTheFunctionDomain
-4(k+5)+6

We multiply parentheses

-4k-20+6

We add all the numbers together, and all the variables

-4k-14

Back to the equation:

-(-4k-14)



We get rid of parentheses

-1k+4k+14+10=0

We add all the numbers together, and all the variables

3k+24=0

We move all terms containing k to the left, all other terms to the right

3k=-24

k=-24/3

k=-8

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