2(b+3)=2(b-3)+5

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Solution for 2(b+3)=2(b-3)+5 equation: 



2(b+3)=2(b-3)+5

We move all terms to the left:

2(b+3)-(2(b-3)+5)=0

We multiply parentheses

2b-(2(b-3)+5)+6=0



We calculate terms in parentheses: -(2(b-3)+5), so:

2(b-3)+5

We multiply parentheses

2b-6+5

We add all the numbers together, and all the variables

2b-1

Back to the equation:

-(2b-1)



We get rid of parentheses

2b-2b+1+6=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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