2(b+3)=-4(b-6)

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Solution for 2(b+3)=-4(b-6) equation: 



2(b+3)=-4(b-6)

We move all terms to the left:

2(b+3)-(-4(b-6))=0

We multiply parentheses

2b-(-4(b-6))+6=0



We calculate terms in parentheses: -(-4(b-6)), so:

-4(b-6)

We multiply parentheses

-4b+24

Back to the equation:

-(-4b+24)



We get rid of parentheses

2b+4b-24+6=0

We add all the numbers together, and all the variables

6b-18=0

We move all terms containing b to the left, all other terms to the right

6b=18

b=18/6

b=3

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