1/3(2x+12)=1/6x

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Solution for 1/3(2x+12)=1/6x equation: 



1/3(2x+12)=1/6x

We move all terms to the left:

1/3(2x+12)-(1/6x)=0



Domain of the equation: 3(2x+12)!=0

x∈R





Domain of the equation: 6x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/3(2x+12)-(+1/6x)=0

We get rid of parentheses

1/3(2x+12)-1/6x=0

We calculate fractions


6x/(36x^2+216x)+(-3x2/(36x^2+216x)=0



We calculate terms in parentheses: +(-3x2/(36x^2+216x), so:

-3x2/(36x^2+216x

We multiply all the terms by the denominator


-3x2

We add all the numbers together, and all the variables

-3x^2

Back to the equation:

+(-3x^2)



We get rid of parentheses

-3x^2+6x/(36x^2+216x)=0

We multiply all the terms by the denominator


-3x^2*(36x^2+216x)+6x=0

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