2(b+2)-(6-b)=-5

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Solution for 2(b+2)-(6-b)=-5 equation: 



2(b+2)-(6-b)=-5

We move all terms to the left:

2(b+2)-(6-b)-(-5)=0

We add all the numbers together, and all the variables

2(b+2)-(-1b+6)-(-5)=0

We add all the numbers together, and all the variables

2(b+2)-(-1b+6)+5=0

We multiply parentheses

2b-(-1b+6)+4+5=0

We get rid of parentheses

2b+1b-6+4+5=0

We add all the numbers together, and all the variables

3b+3=0

We move all terms containing b to the left, all other terms to the right

3b=-3

b=-3/3

b=-1

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