2(b+2)-(6-b)=-4

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Solution for 2(b+2)-(6-b)=-4 equation: 



2(b+2)-(6-b)=-4

We move all terms to the left:

2(b+2)-(6-b)-(-4)=0

We add all the numbers together, and all the variables

2(b+2)-(-1b+6)-(-4)=0

We add all the numbers together, and all the variables

2(b+2)-(-1b+6)+4=0

We multiply parentheses

2b-(-1b+6)+4+4=0

We get rid of parentheses

2b+1b-6+4+4=0

We add all the numbers together, and all the variables

3b+2=0

We move all terms containing b to the left, all other terms to the right

3b=-2

b=-2/3

b=-2/3

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