2(b+1)-8+b=-5

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Solution for 2(b+1)-8+b=-5 equation: 



2(b+1)-8+b=-5

We move all terms to the left:

2(b+1)-8+b-(-5)=0

We add all the numbers together, and all the variables

b+2(b+1)-3=0

We multiply parentheses

b+2b+2-3=0

We add all the numbers together, and all the variables

3b-1=0

We move all terms containing b to the left, all other terms to the right

3b=1

b=1/3

b=1/3

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