5/8(t-24)=1/4(t+12)

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Solution for 5/8(t-24)=1/4(t+12) equation: 



5/8(t-24)=1/4(t+12)

We move all terms to the left:

5/8(t-24)-(1/4(t+12))=0



Domain of the equation: 8(t-24)!=0

t∈R





Domain of the equation: 4(t+12))!=0

t∈R



We calculate fractions


(20tt/(8(t-24)*4(t+12)))+(-8tt/(8(t-24)*4(t+12)))=0



We calculate terms in parentheses: +(20tt/(8(t-24)*4(t+12))), so:

20tt/(8(t-24)*4(t+12))

We multiply all the terms by the denominator


20tt

Back to the equation:

+(20tt)





We calculate terms in parentheses: +(-8tt/(8(t-24)*4(t+12))), so:

-8tt/(8(t-24)*4(t+12))

We multiply all the terms by the denominator


-8tt

Back to the equation:

+(-8tt)



We get rid of parentheses

20tt-8tt=0

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