2(a+4)-3(2a-5)=7+(4a-6)

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Solution for 2(a+4)-3(2a-5)=7+(4a-6) equation: 



2(a+4)-3(2a-5)=7+(4a-6)

We move all terms to the left:

2(a+4)-3(2a-5)-(7+(4a-6))=0

We multiply parentheses

2a-6a-(7+(4a-6))+8+15=0



We calculate terms in parentheses: -(7+(4a-6)), so:

7+(4a-6)

determiningTheFunctionDomain
(4a-6)+7

We get rid of parentheses

4a-6+7

We add all the numbers together, and all the variables

4a+1

Back to the equation:

-(4a+1)



We add all the numbers together, and all the variables

-4a-(4a+1)+23=0

We get rid of parentheses

-4a-4a-1+23=0

We add all the numbers together, and all the variables

-8a+22=0

We move all terms containing a to the left, all other terms to the right

-8a=-22

a=-22/-8

a=2+3/4

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