5(2m-2)=4(m-8)+6

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Solution for 5(2m-2)=4(m-8)+6 equation: 



5(2m-2)=4(m-8)+6

We move all terms to the left:

5(2m-2)-(4(m-8)+6)=0

We multiply parentheses

10m-(4(m-8)+6)-10=0



We calculate terms in parentheses: -(4(m-8)+6), so:

4(m-8)+6

We multiply parentheses

4m-32+6

We add all the numbers together, and all the variables

4m-26

Back to the equation:

-(4m-26)



We get rid of parentheses

10m-4m+26-10=0

We add all the numbers together, and all the variables

6m+16=0

We move all terms containing m to the left, all other terms to the right

6m=-16

m=-16/6

m=-2+2/3

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