2(9q-8)=10+7(6q+10)

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Solution for 2(9q-8)=10+7(6q+10) equation: 



2(9q-8)=10+7(6q+10)

We move all terms to the left:

2(9q-8)-(10+7(6q+10))=0

We multiply parentheses

18q-(10+7(6q+10))-16=0



We calculate terms in parentheses: -(10+7(6q+10)), so:

10+7(6q+10)

determiningTheFunctionDomain
7(6q+10)+10

We multiply parentheses

42q+70+10

We add all the numbers together, and all the variables

42q+80

Back to the equation:

-(42q+80)



We get rid of parentheses

18q-42q-80-16=0

We add all the numbers together, and all the variables

-24q-96=0

We move all terms containing q to the left, all other terms to the right

-24q=96

q=96/-24

q=-4

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