-4(5t-3)+7t=2t-5

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Solution for -4(5t-3)+7t=2t-5 equation: 



-4(5t-3)+7t=2t-5

We move all terms to the left:

-4(5t-3)+7t-(2t-5)=0

We add all the numbers together, and all the variables

7t-4(5t-3)-(2t-5)=0

We multiply parentheses

7t-20t-(2t-5)+12=0

We get rid of parentheses

7t-20t-2t+5+12=0

We add all the numbers together, and all the variables

-15t+17=0

We move all terms containing t to the left, all other terms to the right

-15t=-17

t=-17/-15

t=1+2/15

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