2(9-2z)-3(2z+9)=z-18

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Solution for 2(9-2z)-3(2z+9)=z-18 equation: 



2(9-2z)-3(2z+9)=z-18

We move all terms to the left:

2(9-2z)-3(2z+9)-(z-18)=0

We add all the numbers together, and all the variables

2(-2z+9)-3(2z+9)-(z-18)=0

We multiply parentheses

-4z-6z-(z-18)+18-27=0

We get rid of parentheses

-4z-6z-z+18+18-27=0

We add all the numbers together, and all the variables

-11z+9=0

We move all terms containing z to the left, all other terms to the right

-11z=-9

z=-9/-11

z=9/11

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