-(3b-15)=6(2b+)

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Solution for -(3b-15)=6(2b+) equation: 



-(3b-15)=6(2b+)

We move all terms to the left:

-(3b-15)-(6(2b+))=0

We add all the numbers together, and all the variables

-(3b-15)-(6(+2b))=0

We get rid of parentheses

-3b-(6(+2b))+15=0



We calculate terms in parentheses: -(6(+2b)), so:

6(+2b)

We multiply parentheses

12b

Back to the equation:

-(12b)



We add all the numbers together, and all the variables

-15b+15=0

We move all terms containing b to the left, all other terms to the right

-15b=-15

b=-15/-15

b=1

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