2(8x+5)-3=4(4x-1)+11

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Solution for 2(8x+5)-3=4(4x-1)+11 equation: 



2(8x+5)-3=4(4x-1)+11

We move all terms to the left:

2(8x+5)-3-(4(4x-1)+11)=0

We multiply parentheses

16x-(4(4x-1)+11)+10-3=0



We calculate terms in parentheses: -(4(4x-1)+11), so:

4(4x-1)+11

We multiply parentheses

16x-4+11

We add all the numbers together, and all the variables

16x+7

Back to the equation:

-(16x+7)



We add all the numbers together, and all the variables

16x-(16x+7)+7=0

We get rid of parentheses

16x-16x-7+7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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