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7x(4-3x)=2(8x-9+6
We move all terms to the left:
7x(4-3x)-(2(8x-9+6)=0
We add all the numbers together, and all the variables
7x(-3x+4)-(2(8x-3)=0
We multiply parentheses
-21x^2+28x-(2(8x-3)=0
We calculate terms in parentheses: -(2(8x-3), so:
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| (x+8)×3/4=-12 | | 3(r+2)=5(r-4) | | 2(3x-1)=6x=2 | | 20/z=-5 | | 3x^2+30=x^2-40 | | 8x+14=8x+6 | | 3(1−x)−4(x−5)=9 | | 2x-4(x+3)=×2x-3 | | 5(x+8)×3/4=-12 | | 526b-420=3780 | | 6n–8n+9=37 | | 0,05x+925=0.03+1250 | | 13x+2=121 | | 526b-420=3,780 | | 3(1-x)-4(x-5)=9 | | 26+8x=4x+50 | | 2x-18=72-x | | 2+13x=121 | | 6n–8n+9=37 | | 0.02x+0.7=0.8–0.03x | | 7=1.07^x | | 7d^2-8=0 | | 2x-4(x+3)=×-3 | | 5.7g+4=2.7g+22 | | 8(x-2)=4x+8 | | -7(2x-2)=154 | | 7q^2-q=0 | | 289=50-x | | 10b+(-45)=(-43) | | 15=v/5+13 | | 20y=-4+18Y | | 5x+34=-2(1+7x |