2(7x+1)+12=35+7(x-8)

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Solution for 2(7x+1)+12=35+7(x-8) equation: 



2(7x+1)+12=35+7(x-8)

We move all terms to the left:

2(7x+1)+12-(35+7(x-8))=0

We multiply parentheses

14x-(35+7(x-8))+2+12=0



We calculate terms in parentheses: -(35+7(x-8)), so:

35+7(x-8)

determiningTheFunctionDomain
7(x-8)+35

We multiply parentheses

7x-56+35

We add all the numbers together, and all the variables

7x-21

Back to the equation:

-(7x-21)



We add all the numbers together, and all the variables

14x-(7x-21)+14=0

We get rid of parentheses

14x-7x+21+14=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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