6(x+4)=10(x-2)+3

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Solution for 6(x+4)=10(x-2)+3 equation: 



6(x+4)=10(x-2)+3

We move all terms to the left:

6(x+4)-(10(x-2)+3)=0

We multiply parentheses

6x-(10(x-2)+3)+24=0



We calculate terms in parentheses: -(10(x-2)+3), so:

10(x-2)+3

We multiply parentheses

10x-20+3

We add all the numbers together, and all the variables

10x-17

Back to the equation:

-(10x-17)



We get rid of parentheses

6x-10x+17+24=0

We add all the numbers together, and all the variables

-4x+41=0

We move all terms containing x to the left, all other terms to the right

-4x=-41

x=-41/-4

x=10+1/4

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