2(7w-1)+5w-w(3-3)=w+3(4w+3)+2(3w-9)

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Solution for 2(7w-1)+5w-w(3-3)=w+3(4w+3)+2(3w-9) equation: 



2(7w-1)+5w-w(3-3)=w+3(4w+3)+2(3w-9)

We move all terms to the left:

2(7w-1)+5w-w(3-3)-(w+3(4w+3)+2(3w-9))=0

We add all the numbers together, and all the variables

2(7w-1)+5w-w0-(w+3(4w+3)+2(3w-9))=0

We add all the numbers together, and all the variables

4w+2(7w-1)-(w+3(4w+3)+2(3w-9))=0

We multiply parentheses

4w+14w-(w+3(4w+3)+2(3w-9))-2=0



We calculate terms in parentheses: -(w+3(4w+3)+2(3w-9)), so:

w+3(4w+3)+2(3w-9)

We multiply parentheses

w+12w+6w+9-18

We add all the numbers together, and all the variables

19w-9

Back to the equation:

-(19w-9)



We add all the numbers together, and all the variables

18w-(19w-9)-2=0

We get rid of parentheses

18w-19w+9-2=0

We add all the numbers together, and all the variables

-1w+7=0

We move all terms containing w to the left, all other terms to the right

-w=-7

w=-7/-1

w=+7

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