3(3y-2)=2(4y+6)=

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Solution for 3(3y-2)=2(4y+6)= equation: 



3(3y-2)=2(4y+6)=

We move all terms to the left:

3(3y-2)-(2(4y+6))=0

We multiply parentheses

9y-(2(4y+6))-6=0



We calculate terms in parentheses: -(2(4y+6)), so:

2(4y+6)

We multiply parentheses

8y+12

Back to the equation:

-(8y+12)



We get rid of parentheses

9y-8y-12-6=0

We add all the numbers together, and all the variables

y-18=0

We move all terms containing y to the left, all other terms to the right

y=18

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