2(7+y/3)+3y=1

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Solution for 2(7+y/3)+3y=1 equation: 



2(7+y/3)+3y=1

We move all terms to the left:

2(7+y/3)+3y-(1)=0

We add all the numbers together, and all the variables

2(y/3+7)+3y-1=0

We add all the numbers together, and all the variables

3y+2(y/3+7)-1=0

We multiply parentheses

3y+2y+14-1=0

We add all the numbers together, and all the variables

5y+13=0

We move all terms containing y to the left, all other terms to the right

5y=-13

y=-13/5

y=-2+3/5

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