3(3b+1)=3b-4

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Solution for 3(3b+1)=3b-4 equation: 



3(3b+1)=3b-4

We move all terms to the left:

3(3b+1)-(3b-4)=0

We multiply parentheses

9b-(3b-4)+3=0

We get rid of parentheses

9b-3b+4+3=0

We add all the numbers together, and all the variables

6b+7=0

We move all terms containing b to the left, all other terms to the right

6b=-7

b=-7/6

b=-1+1/6

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