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2(6y+7)=3(4y-5)
We move all terms to the left:
2(6y+7)-(3(4y-5))=0
We multiply parentheses
12y-(3(4y-5))+14=0
We calculate terms in parentheses: -(3(4y-5)), so:We get rid of parentheses
3(4y-5)
We multiply parentheses
12y-15
Back to the equation:
-(12y-15)
12y-12y+15+14=0
We add all the numbers together, and all the variables
29!=0
There is no solution for this equation
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