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1/5x+12=24-3/5x
We move all terms to the left:
1/5x+12-(24-3/5x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(-3/5x+24)+12=0
We get rid of parentheses
1/5x+3/5x-24+12=0
We multiply all the terms by the denominator
-24*5x+12*5x+1+3=0
We add all the numbers together, and all the variables
-24*5x+12*5x+4=0
Wy multiply elements
-120x+60x+4=0
We add all the numbers together, and all the variables
-60x+4=0
We move all terms containing x to the left, all other terms to the right
-60x=-4
x=-4/-60
x=1/15
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