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2(6x-4)+12=12(x+1)
We move all terms to the left:
2(6x-4)+12-(12(x+1))=0
We multiply parentheses
12x-(12(x+1))-8+12=0
We calculate terms in parentheses: -(12(x+1)), so:We add all the numbers together, and all the variables
12(x+1)
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
12x-(12x+12)+4=0
We get rid of parentheses
12x-12x-12+4=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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