2(3x+1)(x+2)-3(4x-5)=0

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Solution for 2(3x+1)(x+2)-3(4x-5)=0 equation: 



2(3x+1)(x+2)-3(4x-5)=0

We multiply parentheses

2(3x+1)(x+2)-12x+15=0

We multiply parentheses ..

2(+3x^2+6x+x+2)-12x+15=0

We multiply parentheses

6x^2+12x+2x-12x+4+15=0

We add all the numbers together, and all the variables

6x^2+2x+19=0

a = 6; b = 2; c = +19;
Δ = b2-4ac
Δ = 22-4·6·19
Δ = -452
Delta is less than zero, so there is no solution for the equation

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