2(6b+2)=4(b-5)-2

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Solution for 2(6b+2)=4(b-5)-2 equation: 



2(6b+2)=4(b-5)-2

We move all terms to the left:

2(6b+2)-(4(b-5)-2)=0

We multiply parentheses

12b-(4(b-5)-2)+4=0



We calculate terms in parentheses: -(4(b-5)-2), so:

4(b-5)-2

We multiply parentheses

4b-20-2

We add all the numbers together, and all the variables

4b-22

Back to the equation:

-(4b-22)



We get rid of parentheses

12b-4b+22+4=0

We add all the numbers together, and all the variables

8b+26=0

We move all terms containing b to the left, all other terms to the right

8b=-26

b=-26/8

b=-3+1/4

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