12x-8(6-4x)=10(2x-8)-20

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Solution for 12x-8(6-4x)=10(2x-8)-20 equation: 



12x-8(6-4x)=10(2x-8)-20

We move all terms to the left:

12x-8(6-4x)-(10(2x-8)-20)=0

We add all the numbers together, and all the variables

12x-8(-4x+6)-(10(2x-8)-20)=0

We multiply parentheses

12x+32x-(10(2x-8)-20)-48=0



We calculate terms in parentheses: -(10(2x-8)-20), so:

10(2x-8)-20

We multiply parentheses

20x-80-20

We add all the numbers together, and all the variables

20x-100

Back to the equation:

-(20x-100)



We add all the numbers together, and all the variables

44x-(20x-100)-48=0

We get rid of parentheses

44x-20x+100-48=0

We add all the numbers together, and all the variables

24x+52=0

We move all terms containing x to the left, all other terms to the right

24x=-52

x=-52/24

x=-2+1/6

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