(n-4)/6=(n-7)/9

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Solution for (n-4)/6=(n-7)/9 equation: 



(n-4)/6=(n-7)/9

We move all terms to the left:

(n-4)/6-((n-7)/9)=0

We calculate fractions


n/()+(-((n-7)*6)/()=0



We calculate terms in parentheses: +(-((n-7)*6)/(), so:

-((n-7)*6)/(

We multiply all the terms by the denominator


-((n-7)*6)



We calculate terms in parentheses: -((n-7)*6), so:

(n-7)*6

We multiply parentheses

6n-42

Back to the equation:

-(6n-42)



We get rid of parentheses

-6n+42

Back to the equation:

+(-6n+42)



We get rid of parentheses

n/()-6n+42=0

We multiply all the terms by the denominator


n-6n*()+42*()=0

We add all the numbers together, and all the variables

n-6n*()=0

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