4(u+1)+5=6(u-1)-+u

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Solution for 4(u+1)+5=6(u-1)-+u equation:



4(u+1)+5=6(u-1)-+u
We move all terms to the left:
4(u+1)+5-(6(u-1)-+u)=0
We use the square of the difference formula
4(u+1)-(6(u-1)-u)+5=0
We multiply parentheses
4u-(6(u-1)-u)+4+5=0
We calculate terms in parentheses: -(6(u-1)-u), so:
6(u-1)-u
We add all the numbers together, and all the variables
-1u+6(u-1)
We multiply parentheses
-1u+6u-6
We add all the numbers together, and all the variables
5u-6
Back to the equation:
-(5u-6)
We add all the numbers together, and all the variables
4u-(5u-6)+9=0
We get rid of parentheses
4u-5u+6+9=0
We add all the numbers together, and all the variables
-1u+15=0
We move all terms containing u to the left, all other terms to the right
-u=-15
u=-15/-1
u=+15

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