2(65-c)=110

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Solution for 2(65-c)=110 equation: 



2(65-c)=110

We move all terms to the left:

2(65-c)-(110)=0

We add all the numbers together, and all the variables

2(-1c+65)-110=0

We multiply parentheses

-2c+130-110=0

We add all the numbers together, and all the variables

-2c+20=0

We move all terms containing c to the left, all other terms to the right

-2c=-20

c=-20/-2

c=+10

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