2(6+2r)=-4(r+3)

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Solution for 2(6+2r)=-4(r+3) equation: 



2(6+2r)=-4(r+3)

We move all terms to the left:

2(6+2r)-(-4(r+3))=0

We add all the numbers together, and all the variables

2(2r+6)-(-4(r+3))=0

We multiply parentheses

4r-(-4(r+3))+12=0



We calculate terms in parentheses: -(-4(r+3)), so:

-4(r+3)

We multiply parentheses

-4r-12

Back to the equation:

-(-4r-12)



We get rid of parentheses

4r+4r+12+12=0

We add all the numbers together, and all the variables

8r+24=0

We move all terms containing r to the left, all other terms to the right

8r=-24

r=-24/8

r=-3

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