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2(5x^2-2)=8x
We move all terms to the left:
2(5x^2-2)-(8x)=0
We add all the numbers together, and all the variables
-8x+2(5x^2-2)=0
We multiply parentheses
10x^2-8x-4=0
a = 10; b = -8; c = -4;
Δ = b2-4ac
Δ = -82-4·10·(-4)
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{14}}{2*10}=\frac{8-4\sqrt{14}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{14}}{2*10}=\frac{8+4\sqrt{14}}{20} $
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