7c+49=7(1+4c)

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Solution for 7c+49=7(1+4c) equation: 



7c+49=7(1+4c)

We move all terms to the left:

7c+49-(7(1+4c))=0

We add all the numbers together, and all the variables

7c-(7(4c+1))+49=0



We calculate terms in parentheses: -(7(4c+1)), so:

7(4c+1)

We multiply parentheses

28c+7

Back to the equation:

-(28c+7)



We get rid of parentheses

7c-28c-7+49=0

We add all the numbers together, and all the variables

-21c+42=0

We move all terms containing c to the left, all other terms to the right

-21c=-42

c=-42/-21

c=+2

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