2(5x-8)-7=4(1-2x)-3(x-2)

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Solution for 2(5x-8)-7=4(1-2x)-3(x-2) equation: 



2(5x-8)-7=4(1-2x)-3(x-2)

We move all terms to the left:

2(5x-8)-7-(4(1-2x)-3(x-2))=0

We add all the numbers together, and all the variables

2(5x-8)-(4(-2x+1)-3(x-2))-7=0

We multiply parentheses

10x-(4(-2x+1)-3(x-2))-16-7=0



We calculate terms in parentheses: -(4(-2x+1)-3(x-2)), so:

4(-2x+1)-3(x-2)

We multiply parentheses

-8x-3x+4+6

We add all the numbers together, and all the variables

-11x+10

Back to the equation:

-(-11x+10)



We add all the numbers together, and all the variables

10x-(-11x+10)-23=0

We get rid of parentheses

10x+11x-10-23=0

We add all the numbers together, and all the variables

21x-33=0

We move all terms containing x to the left, all other terms to the right

21x=33

x=33/21

x=1+4/7

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