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(3x-12)=(x+2)
We move all terms to the left:
(3x-12)-((x+2))=0
We get rid of parentheses
3x-((x+2))-12=0
We calculate terms in parentheses: -((x+2)), so:We get rid of parentheses
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
3x-x-2-12=0
We add all the numbers together, and all the variables
2x-14=0
We move all terms containing x to the left, all other terms to the right
2x=14
x=14/2
x=7
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