2(5x-4)-6(x+2)=7(x-1)+2

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Solution for 2(5x-4)-6(x+2)=7(x-1)+2 equation: 



2(5x-4)-6(x+2)=7(x-1)+2

We move all terms to the left:

2(5x-4)-6(x+2)-(7(x-1)+2)=0

We multiply parentheses

10x-6x-(7(x-1)+2)-8-12=0



We calculate terms in parentheses: -(7(x-1)+2), so:

7(x-1)+2

We multiply parentheses

7x-7+2

We add all the numbers together, and all the variables

7x-5

Back to the equation:

-(7x-5)



We add all the numbers together, and all the variables

4x-(7x-5)-20=0

We get rid of parentheses

4x-7x+5-20=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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