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x2-63x-130=0
We add all the numbers together, and all the variables
x^2-63x-130=0
a = 1; b = -63; c = -130;
Δ = b2-4ac
Δ = -632-4·1·(-130)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-67}{2*1}=\frac{-4}{2} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+67}{2*1}=\frac{130}{2} =65 $
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