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2(5x+3)=-2(2x-4)+3x
We move all terms to the left:
2(5x+3)-(-2(2x-4)+3x)=0
We multiply parentheses
10x-(-2(2x-4)+3x)+6=0
We calculate terms in parentheses: -(-2(2x-4)+3x), so:We get rid of parentheses
-2(2x-4)+3x
We add all the numbers together, and all the variables
3x-2(2x-4)
We multiply parentheses
3x-4x+8
We add all the numbers together, and all the variables
-1x+8
Back to the equation:
-(-1x+8)
10x+1x-8+6=0
We add all the numbers together, and all the variables
11x-2=0
We move all terms containing x to the left, all other terms to the right
11x=2
x=2/11
x=2/11
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