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4(3x+5)=-5(2x-5)+3x
We move all terms to the left:
4(3x+5)-(-5(2x-5)+3x)=0
We multiply parentheses
12x-(-5(2x-5)+3x)+20=0
We calculate terms in parentheses: -(-5(2x-5)+3x), so:We get rid of parentheses
-5(2x-5)+3x
We add all the numbers together, and all the variables
3x-5(2x-5)
We multiply parentheses
3x-10x+25
We add all the numbers together, and all the variables
-7x+25
Back to the equation:
-(-7x+25)
12x+7x-25+20=0
We add all the numbers together, and all the variables
19x-5=0
We move all terms containing x to the left, all other terms to the right
19x=5
x=5/19
x=5/19
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