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2(5x+1)=4(2x+2)
We move all terms to the left:
2(5x+1)-(4(2x+2))=0
We multiply parentheses
10x-(4(2x+2))+2=0
We calculate terms in parentheses: -(4(2x+2)), so:We get rid of parentheses
4(2x+2)
We multiply parentheses
8x+8
Back to the equation:
-(8x+8)
10x-8x-8+2=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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